It takes Bob four hours longer to repair a car than it takes Ken. Working together they cab complete the job in 1.5 hours. How long would each of them take working alone?
Actually, this one will take a bit more thought than the previous one, but the same formula still applies.
B = hours Bob can repair a car alone K = hours Ken can repair a car alone x = What Bob and Ken can repair while working together The formula is: \[\frac{B \times K}{B + K} = x\]
Now, it takes Bob four hours longer to repair so
B = K + 4
We replace B with K + 4 in the formula Also we know x = 1.5
\[\frac{(K + 4) \times K}{K + 4 + K} = 1.5\]
Ok so would I subtract 4 from 1.5? Or make it 4K * K?
Do you know how to expand K(K + 4) ?
You have to expand K(K + 4) for the numerator
SO K^2 + 4K?
Very good
For the denominator you have to add K + K + 4
4K^2?
K + K + 4 = 2K + 4
So what you have is \[\frac{K^2 + 4K}{2K + 4} = 1.5\]
The afterwards, you have to cross multiply to get \[K^2 + 4K = 1.5(2K + 4)\]
From there, you solve for K
K^2+4K=3K+6
Very good. Now subtract 3K from both sides. Then subtract 6 from both sides. After doing that, you should get a quadratic equation of the form ax^2 + bx + c = 0
When you get that, solve for K by factoring or quadratic formula.
K^2+K+6=0 is this right?
Almost. You have to SUBTRACT 6 from both sides.
Ok so would the factoring be. (x+3) (-2)
After subtracting 6 from both sides you should have gotten K^2 + K - 6 = 0
Then by factoring, you would get (K + 3)(K - 2) = 0
Ok I got that. Ok I meant to put K. (Used to using X).
When you solve for K, you must remember that time only makes sense when positive. So keep the positive result and discard the negative result.
Knowing this, what is the correct value of K?
3
Not exactly. You did not solve for K
To Solve for K, you have to use zero product property for (K + 3)(K - 2) = 0
You solve these two equations to find possible values of K K + 3 = 0 K - 2 = 0
-3 and 2 ?
K = -3 or K = 2 But remember, K represents the amount of hours Ken can do the job alone. -3 hours makes no sense.
So only K = 2 makes sense.
Right. So Ken can make the repairs in 2 hours.
Knowing this, how fast can Bob repair the car?
6 hours.
Congratulations. That is correct.
Thanks so much! :)
We can check this \[\frac{2 \times 6}{2 + 6} = 1.5\]
We should get 1.5 for the left side after calculation
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