If y varies directly as x and y=2 when x=-10, find y if x=7.
\(y\) varies directly with \(x\) \[y(x)\propto x\] this means there is a constant \(k\) such that \[y(x)=kx\] to find \(k\), sub in \(y=2\) when \(x=-10\), ie \(y(-10)=-10k=2\)
once you have worked out \(k\), to get \(y\) when \(x=7\), just compute \(y(7)=7k\)
@Hero Could you please explain?
There is an ideal way to explain this
I'll let @SolomonZelman give it a shot first.
y=kx direct variation y=2 when x=-10 so (2)=k(-10) (-1/5)=k the variation is -1/5 now find y if y=(-1/5)7
I'm not good at explaining, sorry.
I don't really need an explanation. What you did was fine. Showing me how to work out the problem is what I wanted explained. Thank you!
Oh, I see, you are similar to me, I can't read a math textbook, but easily follow the unworded work.
Math textbooks are badly organized. That's why. They put the theory and the assignments in the same book.
Almost every textbook I've seen does this.
Yeah, agree.
I think the ideal texbook would have two parts. In the first part, include the theory only. In the second part, include the assignments.
But some people need theory and assignments in the same place.
If they need to do the assignments, they can just flip to the back of the book to do them.
It's wouldn't be that much of a pain to do that
The biggest problem I have with the textbook is they only give a few sample problems. They don't give a sample on all the different problems from each lesson which is hard to learn that way. I am trying to figure out how to do these problems based on the assignment given in the text when I have no idea how to work them out because they don't give good enough of examples. Anyways thanks for the help!
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