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Geometry 20 Online
OpenStudy (anonymous):

( : Could someone help me figure out how the vertex angles of the kite below are bisected by the diagonal.

OpenStudy (anonymous):

OpenStudy (unklerhaukus):

i dont understand the question

OpenStudy (anonymous):

I need to write a two column proof that proves the vertex angles of the kite are bisected by the diagonal.

OpenStudy (anonymous):

make one more diagonal .. it will be proved using property of triangle and kite

OpenStudy (anonymous):

from Q TO S?

OpenStudy (anonymous):

yes ...u will get two isosceles triangles upward and downward of that dia..

OpenStudy (anonymous):

would that be by construction?

OpenStudy (anonymous):

u can also use congruency property .. consider triangle PQR and PSR

OpenStudy (anonymous):

they are congruent by the side side side postulate

OpenStudy (anonymous):

BOTH ARE CONGRUENT BY SIDE ANGLE SIDE PROPERTY

OpenStudy (anonymous):

AND ALSO BY SSS POSTULATE

OpenStudy (anonymous):

THERE CAN BE A LOT OF WAYS TO SOLVE THE PROBLEM

OpenStudy (anonymous):

hm, I'm sorry I'm a little confused. I was thinking they were congruent by the sss postulate because of the 2 pairs of adjacent, congruent sides kites have and PR=PR by the reflexive property

OpenStudy (anonymous):

I didn't see your last few posts before I wrote that, sorry

OpenStudy (anonymous):

u r also ri8 .. this also can be another way to solve .. sss postulate is also applicable there

OpenStudy (anonymous):

how do you break it down from there?

OpenStudy (anonymous):

i m not getting u.. will u please explain??

OpenStudy (anonymous):

where r u studying??

OpenStudy (anonymous):

Florida Virtual

OpenStudy (anonymous):

does this look alright? QP is congruent to PS and QR is congruent to SR |properties of a kite PR is congruent to PR | reflexive property triangle PQR is congruent to triangle PSR| SSS postulate angle QPR is congruent to angle SPR | CPCTC angle QPR+angle SPR= angle QPS| angle addition postulate There fore PR bisects angle QPS into two equal parts because angle QPR = angle SPR.

OpenStudy (anonymous):

YES IT SEEMS RI8

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