Question

Solve by substitution.
x=5y+21
x=5/4y
(it's a fraction)

Answer 1

set them equal to each other and solve for y

Answer 2

set them equal how? sorry i'm really bad with these.

Answer 3

is this (5/4)y or (5/4y) ?

Answer 4

(5/4)

Answer 5

oh wait 5/4y sorry

Answer 6

kk.
\[\large \frak \frac{ 5 }{ 4 }y = 5y + 21\]
Does this help?

Answer 7

a little, the fractions just make it all the more confusing haha.

Answer 8

Just solve for y now
\[\huge \frak \frac{ -15 }{ 4 }y= 21\]
Multiply by the reciprocal.
\[\huge \frak y = \frac{ -84 }{ 15 } = \frac{ -28 }{ 5 }\]

Answer 9

\[\huge \frak x = \frac{ 5 }{ 4 }y\]
\[\huge \frak x = \frac{ 5 }{ 4 } (\frac{-28}{5})\]
\[\huge \frak x = -7\]

Answer 10

okay so then you incorporate -7 into the equation? right?

Answer 11

No, you already have your x and y values.

Answer 12

x = -7
y = -28/5

Answer 13

ohhh okay i see.

Answer 14

thanks :)