Question

I honestly have no clue how to figure this out.

Answer 1

I'm not sure if I'm supposed to be adding or multiplying the two equations.

Answer 2

you're just waiting for answer again LAUGHING OUT LOUD

Answer 3

you did not make any attempt to tackle the problem or learn how to in your previous post

Answer 4

people are going to start refusing on helping you if you don't start helping yourself

Answer 5

I need the process in which to find it. I'm sorry that I didn't really understand what he was trying to explain.

In this problem it says that the device is added, so does that mean I add the h(x) to the c(x) equation? or am I supposed to multiply? Or am I totally wrong and supposed to divide/subtract since it's speeding up the cooling.

I've only worked with problems like this that have the variable in the base, not the exponent.

Answer 6

he was explaining to you the whole thing about log(ab) = log a + log b

Answer 7

see how the multiplication ab turned into addition?

Answer 8

read this one http://www.purplemath.com/modules/logrules.htm

Answer 9

But what is a and b in the equation? Like, is it the base or exponent or argument and how do I find a/b?

Answer 10

So a and b are the arguments in a logarithm?

Answer 11

Do I add the two equations together since it says add, or am I supposed to subtract/divide since it's speeding it up?

Answer 12

@averixx, did you figure it out yet?

Answer 13

Add \(c(x) + h(x)\)

Answer 14

Or rather \(c(5) + h(5)\)

Answer 15

I just tried the addition, and I got .5^-6-5-3 which gave me 56. Which is an answer, so I think it's right.

Answer 16

Great job

Answer 17

I have another question; Given an exponential function for compounding interest, A(x) = P(1.03)x, what is the rate of change? I think it would be 1.03% but I'm not sure, and I'm not sure how to find it.

Answer 18

*how to check it. sorry

Answer 19

The other three options are .003, 103, and 3 . I know it's not 103, because that doesn't make any since. And I'm pretty sure it's not 3.