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Complex numbers question; ω=cos(2π/7)+i sin(2π/7). α=ω+ω^2+ω^4 Find value of 2α=
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\[e^{ix}=cos(x)+isin(x)\] i'd suggest re-writing it as: \[ω=e^{i2π/7}\]
i did so just as you have stated and then tried to solve it but what i need is how to simplify solving alpha
wow, wolfram says it is equivalent to: \[-1 + i\sqrt7\]
yes it is the correct answer but we donot get to use calcs anything else while solving
i'll ask a big gun to check this out. i haven't seen this @Zarkon please shed light if you can
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2 more because I really want to know. come see this please @UsukiDoll and @dan815
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