Question

Can I get help on these problems? =)

Answer 1

ok... so roots are expressed with fractional indices

\[\sqrt[n]{a} = a^{\frac{1}{n}}\]


and knowing that, you can apply it using the power of a power rule.

\[\sqrt[n]{x^a} = (x^a)^{\frac{1}{n}} ... or..... x^{a \times \frac{1}{n}} ..= x^{\frac{a}{n}}\]

hope this helps.

Answer 2

Okay, thank you! =)

Answer 3

So would number 19 be r^4/9?

Answer 4

for question 20 rewrite the terms inside the root

\[\sqrt[4]{x^{11}y^6} = \sqrt[4]{x^8 \times x^3 \times y^4 \times y^2} = \sqrt[4]{x^8y^4}\times \sqrt[4]{x^3y^2}\]

you need to simplify

\[\sqrt[4]{x^8y^4}\]

as you did in question 19

Answer 5

yep... it sure is

Answer 6

Alright, thanks!

Answer 7

for question 21 there are a couple of index rules

1. when dividing, subtract the powers

\[\frac{x^a}{x^{b}} = x^{a - b}\]

then power of a power, which is multiply the powers.

\[(x^a)^b = x^{a \times b}\]

Answer 8

Okay, makes sense! So for 21, is the answer D?

Answer 9

no.... its

\[(x^{-\frac{1}{2} - (-3)})^{\frac{1}{3}}\]

so take care with the division, the power in the answer does have a denominator of 6... so just check your calculations.

Answer 10

Oh, sorry! Thank you, I see what mistake I made now!

Answer 11

question 22.... you need the 5th root... so write x and y in terms of multiples of 5

and there will be another term with a lesser power... similar to question 20

Answer 12

Alright, so is number 21 C then?

Answer 13

yep...

Answer 14

Great! =) I'm working out number 22 now!

Answer 15

Can you help me work out number 22, I'm having a hard time!

Answer 16

ok... so its the 5th root

\[\sqrt[5]{x^{18}y^{13}} = \sqrt[5]{x^{15}y^{10}} \times \sqrt[5]{x^3 y^3}\]

does this helps

Answer 17

Yep definitely!

Answer 18

Is the answer A. x^3y^2√x^3y^3?

Answer 19

it not.... remember... you are taking the 5th root.... and not the square root...as you've shown in your answer

Answer 20

Oh, that's right sorry!

Answer 21

So would the answer be B? =)

Answer 22

correct

Answer 23

Yay! Thank you so much for your help! : )

Answer 24

lol... hope you've learnt a bit

Answer 25

Yeah I did, thanks =)