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Mathematics 17 Online
OpenStudy (anonymous):

This is about vectors

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

I'm not familiar with the notation. What does the down arrow between vectors represents? Cross product?

OpenStudy (anonymous):

its represents the projection of u onto v

OpenStudy (anonymous):

Wouldn't #3 imply that u and v are orthogonal or they are the same?

OpenStudy (anonymous):

whats orthogonal

OpenStudy (isaiah.feynman):

Orthogonal means they are perpendicular.

OpenStudy (abb0t):

Just a fancy word for saying perpendicular, as the person has said above.

OpenStudy (anonymous):

oh okay so then number three implies they are equal

OpenStudy (isaiah.feynman):

Can you draw number three, because I don't know what "projection of v to u" means

OpenStudy (anonymous):

well thats the part on what i don't know how to do

OpenStudy (isaiah.feynman):

Never heard of projection of one vector to another.

OpenStudy (isaiah.feynman):

Number 3 I'd say no.

OpenStudy (anonymous):

sorry what do you mean no?

OpenStudy (isaiah.feynman):

They are not equal

OpenStudy (anonymous):

ohh actually all of those are equal .. its just i have to prove they are equal

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

#3 or #4 ?

OpenStudy (phi):

The projection of vector u onto vector v will be a vector It will point in the same direction as vector v it will have a length | u | cos A where A is the angle between the two vectors |dw:1385558127501:dw| if we call "v hat" the vector v normalized to unit length, we can say \[ u \downarrow v = \left(|u|\ \cos A\right) \hat{v}\]

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