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OpenStudy (anonymous):
@hartnn @jjuden
OpenStudy (anonymous):
@SolomonZelman
OpenStudy (studygurl14):
Is this the equation you need help with, @Jelia97 ?
\[\sqrt{5x+1} -\sqrt{x} = 5\]
OpenStudy (anonymous):
yes thats it
OpenStudy (studygurl14):
Okay, so the first thing you want to do is get rid of the square roots, so you want to square both sides so you get
\[(\sqrt{5x+1} - \sqrt{x})^{2} = 5^{2}\]
\[5x + 1 - \sqrt{5xx+1} - \sqrt{5xx+1} + x\]
What do you do now?
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OpenStudy (studygurl14):
oops, I forgot to put = 25 at the end
hartnn (hartnn):
it would be better if you first add sqrtx on both sides, before squaring both sides
OpenStudy (studygurl14):
What's that @hartnn ?
OpenStudy (studygurl14):
sqrtx?
hartnn (hartnn):
yes
like this
sqrt(5x+1) - sqrt x=5
sqrt(5x+1) = sqrt x+5
now square both sides
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OpenStudy (studygurl14):
Oh, I know what you mean now. Oh, yeah. I probably should have done that first.
OpenStudy (studygurl14):
\[\sqrt{5x + 1} - \sqrt{x} = 5\]
\[\sqrt{5x + 1} = 5 + \sqrt{x}\]
\[(\sqrt{5x + 1})^{2} = (\sqrt{x} + 5)\]
\[5x + 1 = x + 5\sqrt{x} + 5\sqrt{x} + 25\]
Okay, so NOW what do you do?
OpenStudy (anonymous):
is the answer x=16 and x=1
hartnn (hartnn):
16, yes. 1 no
OpenStudy (anonymous):
u sure?? is it just 16
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