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Mathematics 15 Online
OpenStudy (highschoolmom2010):

find the surface are of the cylinders

OpenStudy (highschoolmom2010):

\[SA=2\pi rh+2\pi r^2\] or

OpenStudy (highschoolmom2010):

\[SA=LA+2B\]

hartnn (hartnn):

formula is correct

OpenStudy (highschoolmom2010):

problem is im not sure how to do it

hartnn (hartnn):

you have formula, you have values 17. r=2, h=8

hartnn (hartnn):

in 19th, i think that 7in is the diameter given, you need to find the radius from it

OpenStudy (highschoolmom2010):

\[LA=2 \pi (2*8)\]\[LA=2 \pi (16)\]

hartnn (hartnn):

yes

OpenStudy (highschoolmom2010):

ok so what do i do now that i have that part

hartnn (hartnn):

SA=2πrh+2πr^2 you got 2πrh = 32pi find 2πr^2

OpenStudy (highschoolmom2010):

\[2\pi 9\] \[18\pi\]

hartnn (hartnn):

why did u take r=3 ? :O

OpenStudy (highschoolmom2010):

lol i meant t ill fix it

OpenStudy (highschoolmom2010):

\[2 \pi 4\] \[8\pi\]

hartnn (hartnn):

yesss

OpenStudy (highschoolmom2010):

so now \[32\pi+8\pi=40\pi\]

hartnn (hartnn):

thats absolutely correct for 17th

OpenStudy (highschoolmom2010):

125.663706144 SA=125.7

OpenStudy (highschoolmom2010):

wait i didnt have to do the last part

hartnn (hartnn):

125.7 is approximate answer, only if the answer is not acceptable in terms of pi

OpenStudy (highschoolmom2010):

\[[SA=2\pi (3.5*11)+2(3.5^2)\]

OpenStudy (highschoolmom2010):

it said keep in terms of pi

hartnn (hartnn):

then 40pi is correct and yes, for 19th thats correct too, just simplify

OpenStudy (highschoolmom2010):

\[SA=2\pi (38.5)+2\pi (12.25)\]

OpenStudy (highschoolmom2010):

this is where im confused what to do

hartnn (hartnn):

2(38.5+12.25) = 101.5

OpenStudy (highschoolmom2010):

so \[SA=101.5\pi\]

hartnn (hartnn):

yesss

OpenStudy (highschoolmom2010):

ah thanks again @hartnn for helping :D

hartnn (hartnn):

welcome ^_^

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