Find the absolute maximum and absolute minimum values of f(x)= x^3 - 6x^2 +9x -3 on interval [-1,2
]

Question

Find the absolute maximum and absolute minimum values of f(x)= x^3 - 6x^2 +9x -3 on interval [-1,2
]

anonymous · Answer

f(x)= x^3 - 6x^2 +9x -3
derivate:
3x^2 - (2)x + 9 
set it equal to zero
0=3x^2 - (2)x + 9 
solve for x

shamil98 · Answer

what he said ,lol

anonymous · Answer

i did that and got 3(x-3)(x-1) but then what

anonymous · Answer

my mistake
derivative is:
3x^2 - (2)(6)x + 9 

(forgot the 6)

anonymous · Answer

ya, good
so what are your roots then

anonymous · Answer

well what i did was for the deriv. i got 3x^2 -12x +9. and set it equal to zero to get 3(x-3)(x-1). I believe i should set the (x-3) and (x-1) to zero but i cant remembe rwhat to do with the 3 in the front

anonymous · Answer

you don't need to worry about the 3 infront, just do, 
0=x-3
0=x-1

anonymous · Answer

ohhhhh okay thank you :)

anonymous · Answer

yep ^_^