Which of these ordered pairs is a solution to the inequality 2x + y > – 4 ? A. (0, –5) B. (–1, –1) C. (–3, 0) D. (4, –12)
can someone exlpain how to do this
take each choice, plug it into the equation, and see if the equation is true or false, so, (0, –5) 2(0) + (-5) > – 4 [false] you try the next one..
pick a point of the choices, test it against the inequality, if the inequality turns out to be true, the that point is a solution
2(0) + (-5) > – 4 [false] <--- notice why is false -5 > -4 <----- the closer to the Zero on the negative side, the SMALLER the quantity so -5 is NOT BIGGER than -4, thus is false something yielding false will be say.... like 2 < 0, because 2 is clearly NOT less than 0, is more or 3 < 5, or 6 > 9 and so on a TRUE result will be say 2 > 1 true or 6 < 9 true too
so its b right
hmm lemme reword that a bit -5 > -4 <----- the \(\bf farther\) from Zero on the negative side, the SMALLER the quantity so -5 is NOT BIGGER than -4, thus is false
hmm what did you get for B ?
-3>-4
yeap, -3 is \(\bf closer\) to zero on the negative side, thus is BIGGER than -4
ty so much
yw
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