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Mathematics 15 Online
OpenStudy (anonymous):

am i correct?

OpenStudy (anonymous):

b is the only one that has 2 hours

OpenStudy (anonymous):

because problem 2 is asking how long it would take for one of them to clean it...

jigglypuff314 (jigglypuff314):

yeah, I think you're correct :)

OpenStudy (anonymous):

lol now im not sure how to check it on the second problem with the equation, im not sure how to write it with a decimal

OpenStudy (anonymous):

i was trying 1.5 whitch i think is 15/10 so im not sure how to write that other than 1/15/10

OpenStudy (anonymous):

unless i get the same denominator : t(3t) and distribute it

OpenStudy (anonymous):

i got nothing

jigglypuff314 (jigglypuff314):

brb I'm trying to figure it out... :/ this sort of stuff isn't my strong point...

OpenStudy (anonymous):

ok im looking for a way to do it to :)

OpenStudy (anonymous):

so the amount of time it takes henry: 2/h ammont of time for john: 2/3h if im right 3h stands for the amount of work Henry can do on one pool

OpenStudy (anonymous):

so d

OpenStudy (anonymous):

\[\frac{ 2 }{ h } \times 3h + \frac{ 2 }{ 3t } \times 3h \] so as a result we would have \[2 x 3 + 2 = ?\] so now to solve im still looking

jigglypuff314 (jigglypuff314):

hmm, idk how to solve it but logically it cannot be less than 2hours because no matter how slow john was, he had still contributed and then 8hours sound a bit extreme so if it was me, I would go with A...

OpenStudy (anonymous):

wait i messed up

OpenStudy (anonymous):

that should have been: 2 x 3 + 2 = 2h 6 + 2 = 2h 8 = 2h 8/2 = h 4 = h

OpenStudy (anonymous):

so going back to the original i would have: 2 x 3 + 2 = 1 x 3h 6 + 2 = 3h 8 = 3h 8/3 = h 2.6 = h so ill round it up

jigglypuff314 (jigglypuff314):

looks like I learned something new today ;) Good job!

OpenStudy (anonymous):

there is one other one and its set up as 1/2 + 3/ x = 1 for an example :)

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