Question

Check my answer? I have to rewrite f(x)= 2x^2 + 5x + 3 in general form. This is what I got, am i right?
2. f(x)= 2x^2 + 5x + 3
fx)= 2x^2+5x+3
f(x)= 2x2 +2x +3x +3
f(x) = 2x(x + 1) + 3(x + 1)
f(x) = (2x + 3)(x+1)

Answer 1

I think they want it in 4p(y - k) = (x - h)^2 form

Answer 2

where (h,k) is the vertex and p is the focal distance

Answer 3

explain?

Answer 4

have you seen vertex form before?

Answer 5

yes, but i dont remember what itlooks like

Answer 6

vertex form is

y = a(x-h)^2 + k

where (h,k) is the vertex and 'a' determines the shape and direction the parabola opens up

Answer 7

so what do you get when you convert the given equation into vertex form?

Answer 8

ok yes

Answer 9

i dont know

Answer 10

2x^2 + 5x + 3 is in the form ax^2 + bx + c

in this case

a = 2
b = 5
c = 3

Answer 11

the axis of symmetry is found by this formula

x = -b/(2a)

Answer 12

so what is the axis of symmetry in this case?

Answer 13

-5/(2)(2)

Answer 14

-5/4

Answer 15

that's the x coordinate of the vertex, so h = -5/4

plug x = -5/4 into the original equation, and evaluate to get the y coordinate of the vertex

Answer 16

2(-5/4)^2 + 5(-5/4) + 3

Answer 17

good, keep going

Answer 18

idk how to multiply fractions and whole numbers honestly

Answer 19

think of whole numbers as that number over 1

example: 2 = 2/1

Answer 20

oh ok

Answer 21

-5/2x^2 - 25/4 +3

Answer 22

remember you replaced x with -5/4

Answer 23

oops

Answer 24

-5/2^2 - 25/4 + 3

Answer 25

2(-5/4)^2 + 5(-5/4) + 3

2(25/16) + 5(-5/4) + 3

50/16 -25/4 + 3

25/8 - 25/4 + 3

I'll let you finish this piece up

Answer 26

woah you lost me

Answer 27

sorry, basically I'm following PEMDAS

2(-5/4)^2 + 5(-5/4) + 3 .. plug in x = -5/4

2(25/16) + 5(-5/4) + 3 .. exponents (square-5/4 to get 25/4)

(2/1)*(25/16) + 5(-5/4) + 3 .. change 2 to 2/1

50/16 -25/4 + 3 ... multiplication

25/8 - 25/4 + 3 ... reducing 50/15 to 25/8

Answer 28

hopefully that's a bit clearer