Question

Escape velocity from sun. Rs=7.0 x 10^5 Ms=2.0 x 10^30 kg. I almost solved problem just cant get the right answer with calculating value please help easy medal (;

Answer 1

1/2mv^2 - mGMs/Rs= 0

Answer 2

1/2mv^2=mGMs/Rs

Answer 3

v^2=2GMs/Rs

Answer 4

Vesc= [2GMs/Rs]^1/2

Answer 5

Vesc= {2(2.0 x 10^30)(6.67 x 10^-11)/(7.0 x 10^5)}^1/2

Answer 6

I keep getting a different value than the books answer );

Answer 7

When you say Rs does that mean the radius from the center of the sun? and Ms is the mass? I don't understand your variables

Answer 8

19522880.35 and not sure about untis

Answer 9

Sorry its an escape of the surface of the sun with given radius of sun and mass of sun. They are rounded but thats the values given in problem.

Answer 10

Okay so those are the only two variables given right?

Answer 11

yah

Answer 12

what units are they given in? meters miles? kg pounds?

Answer 13

Rs= 7 x 10^5 km Ms= 2.0 x 10^30 kg

Answer 14

And you're trying to find at what velocity does mass m (our object) have to go to escape the gravitational force of the sun?

Answer 15

yes

Answer 16

what did you put as the gravitational constant of the sun?

Answer 17

6.67x10^-11

Answer 18

I think my error may be that the radius needs to be in meters?

Answer 19

Most likely. You need to change all the variables to similar units. Try that first, and if you still get the wrong answer, just let me know.

Answer 20

got it