Question

Please help me with a two part question

Answer 1

@Directrix

Answer 2

I don't know. What is the two-part question?

Answer 3

@HelloGoodmorning

Answer 4

Oh sorry here let me show you @Directrix

Answer 5

Part 1: Jameel and Sarah are discussing how to factor 3b2 + 8b + 4. Jameel feels this trinomial is prime because he cannot find factors of 4 that have a sum of 8. Sarah says he is incorrect and that it is factorable.

Using complete sentences, provide a convincing argument explaining who is correct and why. If this trinomial is factorable, factor it showing all work and explain your steps.

Answer 6

Jameel feels this trinomial is prime because he cannot find factors of 4 that have a sum of 8.
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Jamel needs to look for factors of 12 (3*4) that add to 8.

ax^2 + bx + c --> Look for factors that multiply to a*c AND add to b.

Answer 7

@HelloGoodmorning What are two numbers that multiply to 12 and also add to 8? Find them so that we can factor, okay?

Answer 8

6 and 2 i'm sorry open study is giving me a hard time posting @Directrix

Answer 9

3b2 + 8b + 4 =

3b² + 6b + 2b + 4 =

3b(b + 2) + 2(b + ?) @HelloGoodmorning

Answer 10

15b^3

Answer 11

That is not what we are doing yet.
2*15b^3 is not equal to 4
Try again.
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2b + 4 = 2(b + ?) @HelloGoodmorning

Answer 12

Ohhh sorry

Answer 13

2 then right @Directrix

Answer 14

3b2 + 8b + 4 =
3b² + 6b + 2b + 4 =
3b(b + 2) + 2(b + 2) =

Notice that (b + 2) is a common factor

(b +2) * ( 3b + 2)

So, Sarah is correct. The polynomial is factorable.

Answer 15

So this would work for the first part?

Answer 16

The first part is just the set-up for part 2. In my mind, it is only one question.

The work is posted already in this thread for the answer.
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From Above
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Jamel needs to look for factors of 12 (3*4) that add to 8.
He forgot this:
ax^2 + bx + c --> Look for factors that multiply to a*c AND add to b.

3b2 + 8b + 4 =
3b² + 6b + 2b + 4 =
3b(b + 2) + 2(b + 2) =
(b +2) * ( 3b + 2)

So, Sarah is correct. The polynomial is factorable.

Answer 17

Loll no sorry that was the first part alone this is the second part which i've been trying to give to you but openstudy is giving me trouble @Directrix Part 2: Create your own prime trinomial in the form ax2 + bx + c. Using complete sentences, explain how you know it is prime.

Answer 18

Try this:

1x^2 + 2x - 1 ---> Try to factor this

Answer 19

Okay

Answer 20

Wait i dont think you can

Answer 21

Am I right @Directrix

Answer 22

It will factor over the set of irrational numbers.

I don't know how prime is defined in your text.

Answer 23

This one, try it:

x^2 + x + 1

Answer 24

Yep that's just it

Answer 25

No its not factorable

Answer 26

and wait it will factor over the set of irrational numbers? Is that what i should put @Directrix

Answer 27

No, don't get into the irrationals.

Answer 28

Use this one instead: x^2 + x + 1

Answer 29

Factor it: x^2 + x + 1

Answer 30

Oh loll how's about this Part 2:
1x^2 + 2x - 1, This trinomial is prime because you are unable to factor it.

Answer 31

Oh ok but i dont know if its factorable @Directrix

Answer 32

That is what you are supposed to explain:

Using complete sentences, explain how you know it is prime.

Answer 33

What are two numbers that multiply to -1 AND add to 2?

Answer 34

There are no two numbers!

Answer 35

So, according to this rule:

ax^2 + bx + c --> Look for factors that multiply to a*c AND add to b.

the expression is prime.

Answer 36

Ohh okay

Answer 37

Thank you very much @Directrix

Answer 38

You are welcome.