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Mathematics 12 Online
OpenStudy (anonymous):

find the slope of the L1 through (1,5) and (1,1) and slope L2 through (-2,2) and (-2,4).determine what types of lines are formed?.

OpenStudy (anonymous):

consider a line A and a line B that are parallel |dw:1385521597071:dw|

OpenStudy (anonymous):

they have the same slope

OpenStudy (anonymous):

when i graph the i got straight line

OpenStudy (anonymous):

consider a line C and a line D that are perpendicular |dw:1385521655471:dw|

OpenStudy (anonymous):

their slopes are negative reciprocals

OpenStudy (anonymous):

they have a solution?

OpenStudy (anonymous):

now we need to find the slope of L1 and L2 and see how their slopes compare

OpenStudy (anonymous):

what solution ??

OpenStudy (anonymous):

no that was just an example to demonstrate the relationship between slopes of lines that are perpendicular or parallel

OpenStudy (anonymous):

do you know how to find the slope of a line?

OpenStudy (anonymous):

formula please ?? the i will show to you if it is correct or wrong

OpenStudy (anonymous):

what is slope

OpenStudy (anonymous):

i told you what slope was in your last question

OpenStudy (anonymous):

do you remember?

OpenStudy (anonymous):

y=mx+b

OpenStudy (anonymous):

that's the equation of a line

OpenStudy (anonymous):

slope is rise/run

OpenStudy (anonymous):

but rise is a change in y-coordinates, and run is a change in x-coordinates

OpenStudy (anonymous):

\[m=\frac{y-y_0}{x-x_0}\] you might recognize this because it's just the point-slope equation of a line rearranged\[y-y_0=m(x-x_0)\]

OpenStudy (anonymous):

i got the anwer its undefined

OpenStudy (anonymous):

try to calculate the slope of L1 that passes through (1,5) and (1,1)

OpenStudy (anonymous):

4/0

OpenStudy (anonymous):

ah k it's basically increasing without bound that's a bit tricky. did you graph the line earlier?

OpenStudy (anonymous):

yes its undefined

OpenStudy (anonymous):

there's an easier way to solve this problem, I was trying to teach you a more general approach that would work for more complex problems but we'll do the more obvious solution

OpenStudy (anonymous):

L1 passes through (1,1) and (1,5)

OpenStudy (anonymous):

|dw:1385522442227:dw|

OpenStudy (anonymous):

it's a vertical line, which is why we're running into problems finding it's slope

OpenStudy (anonymous):

L2 passes through (-2,2) and (-2,4)

OpenStudy (anonymous):

graph it, what does it look like?

OpenStudy (anonymous):

ok ook

OpenStudy (anonymous):

it is not defined

OpenStudy (anonymous):

yeah but what does it look like?

OpenStudy (anonymous):

it's another vertical line which is why we can't get a slope, because its "run" is zero

OpenStudy (anonymous):

vertical lines

OpenStudy (anonymous):

right so what sort of relationship do L1 and L2 have?

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

the question asks you to compare the slopes of L1 and L2 to determine what sort of lines are formed

OpenStudy (anonymous):

we can't find the slopes since we can't divide by zero, but we can compare the lines

OpenStudy (anonymous):

vertical lines?

OpenStudy (anonymous):

by graphing, and see what kind of relationship they have

OpenStudy (anonymous):

are they parallel, perpendicular, or neither?

OpenStudy (anonymous):

neither

OpenStudy (anonymous):

do you know the mathematical symbol for "parallel"? It's ||

OpenStudy (anonymous):

Looks kind of like L1 and L2 ;)

OpenStudy (anonymous):

no

OpenStudy (anonymous):

they are parallel??

OpenStudy (anonymous):

we couldn't find their slopes exactly, but we can see they have equal slopes|dw:1385523025372:dw|

OpenStudy (anonymous):

what types of lines are formed??

OpenStudy (anonymous):

I would say "parallel vertical lines" for completeness' sake

OpenStudy (anonymous):

what? what are they?

OpenStudy (anonymous):

@Xeph

OpenStudy (anonymous):

Yes?

OpenStudy (anonymous):

tparallel vertical lines?

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