Question

2|x − 6| + 14 = 38

Answer 1

2(x^2 +36) +14 =38
2(x^2+36) =38-14
x^2 + 36= 24\2
x^2 +36 = 12
x^2 =12-36
x^2 = -24
tkaing square root on both sides
\[\sqrt{x ^{2}}=\sqrt{2 \times 2 \times 2 \times-3 }\]
\[x = 2 \sqrt{-6} \]
or
x=\[x = 2\sqrt{6}\iota \]
so the root is imaginary

Answer 2

THANKS !!!! :)

Answer 3

You sure @Haseeb96 ?

Answer 4

yes 100%

Answer 5

2|x-6| = 24
|x-6| = 12
consider two cases again
x-6 = 12
-(x-6) = 12
x = 18
and
x = -6

Answer 6

It's just about absolute values. @Haseeb96

Answer 7

yttrium there first we apply Modulus

Answer 8

I x -6 I = 12
I I is the sign of modulus

Answer 9

is it really modulus @Goldenmoon or and absolute value?
what your lesson is?

Answer 10

The answer was wrong , its absolute value :/ sorry

Answer 11

Then follow what I've writtern here @Goldenmoon

Answer 12

I did , it was correct . Thank you.

Answer 13

No prob. :))