Question

help!??!

Answer 1

@Ryan2416 ?

Answer 2

Thats a division sign right?

Answer 3

Factorizing numerator and denominator of the first term we get
\[\frac{(x+4)(x-3)}{(x-5)(x+4)}=\frac{x-3}{x-5}\ ...........(1)\]

Answer 4

The second term can be factorized as follows:
\[\frac{3(x ^{2}-8x+15)}{12(x ^{2}-4x-5)}=\frac{x-3}{4(x+1)}\ ........(2)\]
Now you need to divide the expression in (1) by the expression in (2).
Can you do that?