Question

Quick Question.
When factoring an expression, what do you do if you don't have "C"? Do you just put a 1 in?

Answer 1

what is C

Answer 2

2c + c

c(2 + 1)

Answer 3

Well I don't have "C" that's the problem. The base equation is ax^2 + bx + c but I only have ax^2 + bx.

Answer 4

I see

Answer 5

if it is absent then it is 0

Answer 6

But how do I use 0? I mean if it is 0 then I won't get a number for GCf.

Answer 7

I thought it couldn't be 0.. But I may be wrong.

Answer 8

usually what exactly do you do with gcf ?

Answer 9

You take GCF and use it to find your set of pairs in the factored form.

Answer 10

(x+ )(x+ )

Answer 11

Say I had 4x^2 + 11x + 6 as an equation. I would times A & C to get 24(GCF). Then I would take 24 and find its factors and their sums.
1 x 14, 2 x 12, 3 x 8.
3 x 8 = 24 3 + 8 = 11
So, the equation would go to: 4x^2 + 3x + 8x + 6
The to: x(4x +) 2(4x + 3)
and then: (x + 2) (4x + 3) as the finial answer.
But for this one I need help with, I don't have "C".

Answer 12

Ops 1 x 24 not 1 x 14 ha

Answer 13

@d0nt_h8_my_sw4g Can you help me?

Answer 14

@mathessentials ?

Answer 15

sorry I don't know much about this...

Answer 16

Okay, do you know someone who could help??

Answer 17

x^2 = xx

axx + bx, has x as a common factor

x(ax+b)

Answer 18

or if you want a binomial ..

(x+0)(ax+b)