Question

3 - 23sin(x) = 0

Answer 1

it also says Solve the following trigonometric equation for the interval
(0,2].

Answer 2

anybody out there to help me

Answer 3

If you simplify, you get sin(x) = 3/23.

So, there is some triangle that looks like this:
Using the inverse sine (arcsine), we find that x = 0.131 rad = 7.5 degrees.
This could also occur in the 2nd quadrant, so 180-7.5 = 172.5 degrees
or 1.44 radians.

Answer 4

no

Answer 5

my answer choose are



4
;
3

4



B.



3
;
2

3



C.



6
;
11

6



D.



3
;

Answer 6

I mean are pie over 4 and 3pie/4 that's a

Answer 7

b says pie/3 and 2pie/3

Answer 8

next one says pie/6 and 11pie/6

Answer 9

last one pie/3 and pie/6

Answer 10

are you sure it is 3 and 23?

Answer 11

3 - 23sin(x) = 0

that's the problem

Answer 12

nun about 23

Answer 13

hmmmm..... sorry, i don't know what to say.

Answer 14

did you look at the answer choose

Answer 15

ill give you a medal please

Answer 16

helpppppppppppppppppppppppppppppppppppppppppppp somebody

Answer 17

Solve the following trigonometric equation for the interval
(0,2].
3 - 23sin(x) = 0

Answer 18

help

Answer 19

ok the answer is:
\[x=2 \pi n+\pi-\sin ^{-1}(\frac{ 3 }{ 23 })\]
where;
\[n \in \mathbb{Q} \]

Answer 20

so i think its 2pie/3

Answer 21

my answer choice are pie/4 and3pie,4 that's a

Answer 22

anwer chosie b are pie/3 and 2pie/3

Answer 23

c is pie/6 and 11pie/6

Answer 24

d is pie/3 pie/6

Answer 25

so what do think it is

Answer 26

help