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Mathematics 16 Online
OpenStudy (anonymous):

Can some help me with Math???????

OpenStudy (anonymous):

Depends..............

OpenStudy (isaiah.feynman):

This is intuitive really, Myrtle must increase the initial velocity of the ball!

OpenStudy (anonymous):

v_i = 2m/s h_i=6m h = -5t2 + 2t + 6 "Myrtle wants to know with what velocity she must throw the ball to make it pass over a tree that is 11 m tall" h_max=11m to figure out if we need to increase velocity or decrease, we first need to figure out the maximum height the ball goes when just throwing it normal. to find the 'maximum', take the derivative of the equation: h = -5t2 + 2t + 6, then set it equal to zero, then solve for x. can you do this for me?

OpenStudy (anonymous):

This question has been bothering for a few days, so can you give your input in this?

OpenStudy (anonymous):

me or.. Isaiah?

OpenStudy (isaiah.feynman):

Choose demolisionWolf. lol

OpenStudy (jdoe0001):

hehe

OpenStudy (anonymous):

what kind of 'math' class is this?

OpenStudy (anonymous):

LOL anyone! just please help me with this :)

OpenStudy (jdoe0001):

hmmmm on what chapter is this being covered?

OpenStudy (agent0smith):

I just wrote out a solution and then accidentaly clicked another question and lost it. I'm not typing it all again. you need to get this into vertex form to find v, where the maximum value of h is 11 \[\Large h = -5t^2 +vt +6\] completing the square gives \[\Large h = -5(t -\frac{ v^2 }{ 100 })^2 +6 +5\frac{ v^2 }{ 100 }\] that whole end chunk needs to equal the max value of 11 for the quadratic \[\Large 6 +5\frac{ v^2 }{ 100 } = 11\] find v. This is the minimum required velocity to clear 11m

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