When a piece of metal is irridiated with UV radiation (lambda=162 nm), electrons are ejected with a kinetic energy of 5.34*10^-19 J. What is the work function of the metal.

I am thrown off by the wavelength. I changed it to m/s instead of nm but am unsure what to do with it from there.

Question

When a piece of metal is irridiated with UV radiation (lambda=162 nm), electrons are ejected with a kinetic energy of 5.34*10^-19 J. What is the work function of the metal. 

I am thrown off by the wavelength. I changed it to m/s instead of nm but am unsure what to do with it from there.

anonymous · Answer

$$K=hf- \Phi$$
Phi is the work function, f is the frequency of the radiation, and K is the kinetic energy of the ejected electrons.

For the photon
$$c=f\lambda$$