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Mathematics 7 Online
OpenStudy (anonymous):

help me with this? i think i have to factor out 2x - x+5

OpenStudy (anonymous):

OpenStudy (cwrw238):

the numerator will be 2x(x+3) - (x+5)(x-2) simplify this

OpenStudy (cwrw238):

- and place it over (x-2)(x+3)

OpenStudy (anonymous):

\[\frac{ 2x }{ (x-2) } x (x+3) - \frac{ (x+5) }{(x+3) } (x + 2) \] so i think that i would have 2x - x+5 / x+3 (x +2)

OpenStudy (anonymous):

what do you think @cwrw238 ?

OpenStudy (anonymous):

wait thats wrong i would have: 2x^2 + 6x - (x^2 - 2x +5x - 10) on the top and that should equal: 2x^2 + 6x - x^2 + 3x - 10 x^2 + 6x + 3x - 10 but after that i still dont have an answer

OpenStudy (cwrw238):

your second line is incorrect you have to distribute -1 over the parentheses so it should be 2x^2 + 6x - x^2 -3x + 10

OpenStudy (jdoe0001):

\(\bf \cancel{(x-2)}(x+3)\left(\cfrac{2x}{\cancel{x-2}}\right)-(x-2)\cancel{(x+3)}\left(\cfrac{x+5}{\cancel{x+3}}\right)\)

OpenStudy (anonymous):

did the site just go down?

OpenStudy (jdoe0001):

yes

OpenStudy (anonymous):

lol wow

OpenStudy (jdoe0001):

just a quick downtime, it happens now and then, servers need to be maintained, so

OpenStudy (anonymous):

i see, and i also see i had it my equation incorrectly

OpenStudy (anonymous):

*incorrect

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