Question

ok, what do i factor or where do i begin

Answer 1

Ok lets try to factor each numerator and denominator and then simplify

Answer 2

So lets start off with the first one \( c^2-4\)

Answer 3

so on the first would i factor c^2 - 4 as :
(c + 2)(c - 2)
c^2 - 2c + 2c - 4
c^2 - 4

am i correct

Answer 4

We know the rule \( a^2-b^2=(a-b)(a+b)\)
So we can say that \(c^2-2^2=(c-2)(c+2)\)

Answer 5

YUP :)

Answer 6

i need help

Answer 7

lol ok

Answer 8

Can you please delete that?
Its disturbing our thought process here

Answer 9

We dont know the answer sorry kid

Answer 10

Ok the next term is \(6c^4+15c^3\)
Now we can factor out a 3 and a "c"
\(6c^4+15c^3 = 3c^3(2c+5)\)

Answer 11

Do ya follow?

Answer 12

so you divided both sides by 3?

Answer 13

i mean both 6 and 15

Answer 14

Umm you can look at it like that if that makes sense to you

Answer 15

Its basically the opposite of distributing

Answer 16

ok so now i would have:

(c + 2)(c - 2)
------------
3c^3 (2c + 5)

Answer 17

Yup now lets factor the second term

Answer 18

\(c^2+4c+4\)

Answer 19

Familiar with perfect square?

Answer 20

ok i see or at least i think i do

i need to find out what is needed to foil that would equal c^2 + 4c + 4