Question

verify the equation is an identity: sin (x)/1-sin ^2 (x)

Answer 1

is it \[\frac{ \sin x }{ 1-\sin^2x }\]

Answer 2

yes

Answer 3

Is tan x, considered an identity?

Answer 4

I think so

Answer 5

we have to know, it would be equals what ?

Answer 6

sec x tan x

Answer 7

sorry

Answer 8

okay, that makes more sense.

Answer 9

use these identities :
1 - sin^2 x = cos^2 x
sin/cos = tan
1/cos = sec

Answer 10

pretty much, should not take more than 4 steps.

Answer 11

sin (x)/1-sin ^2 (x)
= sin (x)/cos^2 x
= sin(x)/cos(x) * 1/cos(x)
= tan(x) sec(x)

Answer 12

or sec x tan x
1/cos x sin x /cos x
sinx / cos 2x
sinx / 1-sin2x

Answer 13

what we have here is simply a simplification trig problem... wherein we simplify...
\[\frac{ \sin x }{ 1-\sin^2x }=\sec x \tan x\]

Answer 14

I mean cosx squared and sin x squared not double angle.

Answer 15

using trig identity of course... :)