Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

A textbook company keeps track of its daily cost for printing whole textbooks to different schools but can only print up to 500 books a day. The daily cost (C) to print x number of textbooks is given by C(x) = 3.50x + 1200. Using the function, determine one possible daily cost by evaluating the function for any input of your choice. A. For what value of x does C(x) = 1900? B. Interpret the statement C(20) = 1270. C. Interpret the statement C(w) = p. D. Explain whether C(40.5) = 1341.75 is correct and possible given the context of this problem.

OpenStudy (alekos):

A. x = 200

OpenStudy (alekos):

b: cost of 20 books is 1270

OpenStudy (alekos):

C: the cost of printing w books equals p

OpenStudy (alekos):

D; no , because you cant print 1/2 a book

OpenStudy (anonymous):

thank you! :) can you help with -> Using the function, determine one possible daily cost by evaluating the function for any input of your choice.

OpenStudy (anonymous):

among the 4 choices you provide, which will give you a real evaluation of the function?

OpenStudy (anonymous):

the textbook company can print up to 500 books in a day... which is more than 20 or 200...

OpenStudy (anonymous):

and the last choice is not possible as @alekos said...

OpenStudy (anonymous):

so which choice will give you the real evaluation of the function? what do you think?

OpenStudy (anonymous):

like which of those answers? c?

OpenStudy (anonymous):

why do you think so?

OpenStudy (anonymous):

because you said 200 and 20 isnt enough and a is 20 and b is 200 so it must be c

OpenStudy (anonymous):

yes it is C, because the w as the number of books is simply a variable like x that can interpret the number of books that can be print daily, it ranges from 1 to 500... and the C(w)=p, represents the corresponding daily cost...

OpenStudy (anonymous):

w is a positive integer (number with no fractions)....

OpenStudy (anonymous):

got the idea @emmmerrss ?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!