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Mathematics 16 Online
OpenStudy (anonymous):

Two numbers are reciprocals if their product is equal to 1, If x and y are reciprocals and x >1 then y must be?

OpenStudy (skullpatrol):

Any ideas?

OpenStudy (anonymous):

less than 1

OpenStudy (skullpatrol):

Correct.

OpenStudy (skullpatrol):

But, there is still one more restriction on y, can you tell me what it is?

OpenStudy (skullpatrol):

$$?\lt y \lt 1$$

OpenStudy (anonymous):

less than 0

OpenStudy (skullpatrol):

What goes where the question mark is?

OpenStudy (skullpatrol):

$$\Huge xy=1$$ and x >1 then y must be?

OpenStudy (skullpatrol):

@LilySwan Are you still there?

OpenStudy (anonymous):

reciprocals that would +1 and -1 right ?

OpenStudy (skullpatrol):

would what?

OpenStudy (skullpatrol):

The only numbers that are reciprocals of themselves are +1 and -1.

OpenStudy (anonymous):

right so that would mean it is less than -1

OpenStudy (skullpatrol):

No.

OpenStudy (skullpatrol):

Numbers that are less than -1 are -1.5, -2, -3, -4,...

OpenStudy (anonymous):

so 0

OpenStudy (skullpatrol):

What is zero times any number?

OpenStudy (anonymous):

i mean between o and 1

OpenStudy (skullpatrol):

Exactly correct. Between 0 and 1.$$\Huge 0\lt y\lt1$$

OpenStudy (anonymous):

that means if x < 1 than y is greater than 0 and less than 1

OpenStudy (skullpatrol):

Does it?

OpenStudy (skullpatrol):

Remember xy = 1 by the definition of a reciprocal.

OpenStudy (anonymous):

so than y should also be less than 1

OpenStudy (skullpatrol):

No, x and y just switch roles.

OpenStudy (skullpatrol):

if 0< x <1 then y >1

OpenStudy (anonymous):

ok thanks

OpenStudy (skullpatrol):

Thanks for trying to understand this very profound result which says the interval from 0 to 1 can be paired with all the numbers greater than 1...

OpenStudy (anonymous):

|dw:1385631731602:dw|

OpenStudy (anonymous):

this number line shows -1>= x or 3<=x

OpenStudy (anonymous):

how?

OpenStudy (skullpatrol):

Rather than writing it like you did as " -1>= x or 3<=x" Try to think of it as x is <= -1 OR x is >=3. Then x must be in the shaded parts, right?

OpenStudy (anonymous):

0<y<1

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