Question

Please factor this equation. y=-2x^2-4x+3

Answer 1

well the problem that you have is that it won't factor...

other than taking -1 out as a common factor

Answer 2

You can expand it.

Answer 3

because I had a vertex equation y-5=-2(x+1)^2 and i already changed it standard form making it y=-2x^2-4x+3 and now I want to change it to intercept form

Answer 4

an example of an intercept form is (x+2)(x-3)

Answer 5

nvm you can't expand it. Lol

Answer 6

Ah intercept form is what I was thinking about.

Answer 7

do you know how to complete the squares>

Answer 8

no that was the problem

Answer 9

so after you completed the squares you still were unable to change it to intercept form?

Answer 10

I dont know how to complete the square

Answer 11

so you take half of -4x and then square it, add it to both sides.

Answer 12

http://www.youtube.com/watch?v=xGOQYTo9AKY

Answer 13

Only take half of the integer. (the#)

Answer 14

I got y= -2( x^2 + 2x -1.5 )

Answer 15

Can you please show me your work?

Answer 16

I just divided everything by -2

Answer 17

Oh okay. It looks good

Answer 18

Did completing the squares help out

Answer 19

I dont know where to go from there

Answer 20

The formula states that (a+b)^2=a^2+2ab+b^2
In this case a=x. What you want to do is to retrieve the 'b' from the term you got (aka 2x)
So 2x=2ab=2xb you get b=1
After that you add the b and you retrieve it like this:
y= -2( x^2 + 2x -1.5 ) = -2( (x^2 + 2*x*1 + 1) - 1 -1.5)
Can you take it from here ?

Answer 21

No :(

Answer 22

y= -2( x^2 + 2x -1.5 ) = -2( (x^2 + 2*x*1 + 1) - 1 -1.5) = -2((x+1)^2 - 2.5 )
= -2(x+1)^2 +5