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How would you solve arccos
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@jennisicle do you understand the concept of inverse trigonometric ratios?
Not really, it's kind of confusing to me
I somewhat understand it
Solving this problem requires understanding inverse functions. If you need background info on inverse functions, please ask. Now, if arccos(2x-1) = Pi/3, we can solve for (2x-1) by taking the cosine of both sides of this equation. We get 2x-1 = cos(Pi/3), and cos(Pi/3)=cos(60 degrees) = 1/2. So this problem boils down to 2x-1=1/2. Solve that for x and you'll be done.
Alright, I wasn't sure if cos cancelled out arccos but that makes sense. Thanks!
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