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Mathematics 11 Online
OpenStudy (anonymous):

Differentiate each function;

OpenStudy (anonymous):

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OpenStudy (mathmale):

This function is first and foremost a PRODUCT. We could also write it as x/e^(x^2), a QUOTIENT. Try applying the quotient rule to the latter expression. Let me know whether or not this makes sense.

OpenStudy (anonymous):

@mathmale I see that a product rule is applied first then a chain rule but I am not sure how to start.

OpenStudy (mathmale):

Please review the product rule. I'll summarize it here: (uv)' = uv' + vu' In the function you present, u = x and v = e^(x^2). u' = 1 and v' = e^(x^2) * (x^2)' (which is an application of the chain rule). Can you take the problem solution from here?

OpenStudy (anonymous):

@mathmale so is the setup like this; x(d/dx(e^(x)^(2))+e^(x)^(2)(d/dx(x))

OpenStudy (mathmale):

Your handwritten expression is the better one, as you've used hand-drawn parentheses perfectly there. Now please find the two derivatives (each one inside a BIG set of parentheses) and simplify the result. Just one oversight: that's e^(-x^2) [not e^(x^2), if you're using the product rule. Otherwise you're right on target!!

OpenStudy (anonymous):

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