Question

A particle is moving along the curve y= 5 \sqrt{4 x + 4}. Let D be the distance from the location of the particle on the curve to the origin.
As the particle passes through the point (3, 20), its x-coordinate increases at a rate of 2 units per second. Find the rate of change of D at this instant.

Answer 1

think you can help me @Isaiah.Feynman ?!

Answer 2

Sure.

Answer 3

Remember the distance formula?

Answer 4

yes!

Answer 5

sqrt( (x2-x1)^2 + (y2-y1)^2 )

Answer 6

Good. Differentiate it implicitly.

Answer 7

yes use related rates