Question

Solve the problem Helpp plzzzz An initial investment of $14,000 is appreciated for 12 years in an account that earn 10% interest, compounded semiannually . find the amount of money in the account at the end of the period

Answer 1

\(F = P(1 + \dfrac{r}{n})^{nt} \)

F = future value
P = present value
r = annual interest rate written as decimal
n = number of compounding periods in one year
t = number of years

Answer 2

I dont got it

Answer 3

well plug in the values in question to the formula that math student gave you
eg:
P = 14,000
r = 0.10 ( 10% written as a decimal)

can you tell me what n and t are?

Answer 4

n= number of compounding periods in one year
t = number of years

Answer 5

ok and what is the values of these ( check the question)

Answer 6

n=?
t=12

Answer 7

n = 2 ( semiannually means 2 times a year)

Answer 8

so plug these values in and use ur calculator to find the value of F

Answer 9

s its

F = 14000(1 + ( 0.10/2))^24

Answer 10

how did u get 24

Answer 11

i'm confused

Answer 12

nt - that is n times t = 2*12 = 24

Answer 13

i got it now

Answer 14

good

Answer 15

the answer will be 14000

Answer 16

no
you work out
14000(1 + 0.05)^24 using your calculator

Answer 17

the amount at end of the period = F
which is given by the formula

Answer 18

45151.4

Answer 19

right

Answer 20

\(F = P(1 + \dfrac{r}{n})^{nt}\)

\(P = $14,000\)
\(r = 10\% = 0.1\)
\(n = 2\)
\(t = 12\)

\(F = $14,000 \left(1 + \dfrac{0.1}{2} \right)^{2 \times 12} \)

\(F = $45,151.40\)