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The force F = 4 i + 2 j moves an object 3 ft along the x-axis in the positive direction. Find the work done if the unit of force is the pound.
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Work is defined as:\[W=\vec{F}\cdot \vec{d}\]
Work done is scalar = Force . Displacement = | Force | * |Displacement| * cos theta Theta = angle between force and displacement. Or do it by the dot product method. [Which is much faster] If Force [F] = Fx + Fy + Fz Displacement [S] = Sx + Sy + Sz Then work done is their dot product which is = Fx*Sx + Fy*Sy + Fz*Sz [That is multiply their magnitudes] Got it? :D
Here you have F = 4i + 2j OR 4x + 2y Displacement is along x axis so S = 3x or 3i Now simply find the dot product by the latter method! :D
12 right for the dot method?
correct
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