[ d/dx]( ( 4√{x} ) ln(x)) = ? 4 is the upper on the square root so it means 1/4
Alright. So you'll just need to use the product rule, right?
But I have no idea how to do it..
OK, do you know what the product rule is?
Yea. Oh wait the question is [ d/dx]( ( 4√{x} )^(ln(x))) so it should be power rule
You actually have to use both the power rule and the product rule:\[\frac{d}{dx}(\sqrt[4]{x}\ln(x))=\frac{d}{dx}(\sqrt[4]{x})*\ln(x)+\sqrt[4]{x}*\frac{d}{dx}(\ln(x))\]Does that help?
So is it 1/4x^(-3/4)(ln(x))+x^(3/4).?
The right term should be this, I believe:\[x^{1/4}*\frac{1}{x}=x^{-3/4}\]
1/4x^(-3/4)(ln(x))+x^(-3/4.? But it is still incorrect...
No, that's right: http://www.wolframalpha.com/input/?i=d%2Fdx%28x%5E%281%2F4%29*ln%28x%29%29
Um...? The web work said wrong...
Wait... The question is to the power of ln(x)
Write it out?
Join our real-time social learning platform and learn together with your friends!