Hello there
I need help verifying my answer to this problem. using a coordinate plane find the hypothenus of a right triangle whose vertices are A(1,1) B(13,1) C(13,6). I got 49 but the author says its 13.

Question

Hello there
I need help verifying my answer to this problem. using a coordinate plane find the hypothenus of a right triangle whose vertices are A(1,1) B(13,1) C(13,6). I got 49 but the author says its 13.

anonymous · Answer

If you plot the point, you should see that the right angle is at B. That means that AC is the hypotenuse.

Use the distance formula for points A and C and you will get 13.

Sqrt((13-1)^2 + (6-1)^2)
Sqrt(144 + 25)
Sqrt(169)
13

anonymous · Answer

The dimensions are x=12 and y=5.  Use pythagorus to verify your answer.

kc_kennylau · Answer

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kc_kennylau · Answer

I guess you got $49$ by squaring $(12-5)$, am I right? :)

anonymous · Answer

The distance formula for AC is the formula having different x and y coordinates. So I have 7 for the answer and squared is 49

kc_kennylau · Answer

I apologize for not being able to comprehend your last sentence :/

kc_kennylau · Answer

What is the formula that you are taught?

anonymous · Answer

hold on please im drawing it for you

anonymous · Answer

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