Hey there
I need help with this distance btw 2 points.

Question

Hey there
I need help with this distance btw 2 points.

anonymous · Answer

$$(\sqrt{3}, \sqrt{2}) and (\frac{ 2 }{ \sqrt{3}} ,-\sqrt{2})$$

kc_kennylau · Answer

$$d=\sqrt{(y_2-y_1)^2-(x_2-x_1)^2}$$

anonymous · Answer

I did that and I got two different answers than the book

anonymous · Answer

I have no clue how to solve this correctly

kc_kennylau · Answer

What did you get? :)

anonymous · Answer

waitt. Kenny how come you are subtracting them? you are suppose to add them

anonymous · Answer

No harsh the answer in not 1

kc_kennylau · Answer

oh sorry

kc_kennylau · Answer

$$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$$

anonymous · Answer

"...got two different answers than the book"

anonymous · Answer

i got the ans 11/3

kc_kennylau · Answer

$$\sqrt{(-\sqrt2-\sqrt2)^2+(\frac2{\sqrt3}-\sqrt3)^2}$$$$=\sqrt{8+\frac13}$$$$=\sqrt{\frac{75}9}$$$$=\frac{5\sqrt3}3$$

anonymous · Answer

Still wrong Harsh

anonymous · Answer

Correct answer Kenny but...did you distribute?

anonymous · Answer

OHH! well Kenny Thank you again for helping =) i need a break...

kc_kennylau · Answer

$$\sqrt{(-\sqrt2-\sqrt2)^2+(\frac2{\sqrt3}-\sqrt3)^2}$$$$=\sqrt{(-2\sqrt2)^2+(\frac{-1}{\sqrt3})^2}$$$$=\sqrt{8+\frac13}$$

kc_kennylau · Answer

no problem :)

anonymous · Answer

Kenny at first glance I thought I understood, now I am confused. What did you do?

kc_kennylau · Answer

Where did you not understand?

kc_kennylau · Answer

Sorry I have to sleep now, please bump to the top so that people can help you

anonymous · Answer

oK good night