Question

Solve the system of equations using matrices. Use Gauss-Jordan elimination.

3x - 7 - 7z = 7
6x + 4y - 3z = 67
-6x - 3y + z = -62

Answer 1

@da_ScienceMan

Answer 2

this is similar to that question @da_ScienceMan

Answer 3

just tell me how to start and i will try to solve it

Answer 4

ok hi. Did u try to go through the other one? and did u verify the steps? I was really in a rush!

Answer 5

i did with my cousin but i didnt get it very clear... but i will try my best to solve this one and see if i can do it myself

Answer 6

just tell me how to start of

Answer 7

@da_ScienceMan u der

Answer 8

yes it is almost like the method yesterday....just begin by writing down the augmented matrix.

Answer 9

i mean wxyz that way

Answer 10

\[\left[\begin{matrix}3 & -7 & -7 | 7 \\ 6 & 4 & -3 | 67 \\ -6 & -3 & 1 | -62 \end{matrix}\right]\]

Answer 11

so have u written d the matrix i just typed? we can proceed...this one is shorter than the one we had yesterday!

Answer 12

@Yacoub1993 u there?

Answer 13

yes i am there, solving the thread

Answer 14

ok so we begin by multiplying row 1 by 2 and adding to row 3. But we keep our row 1 the same as the old matrix. Only row 3 is permitted to change! Next, we multiply row 1 by -2 and add to row 2. Only elements in row 2 are permitted to change. All other rows from the previous step remain unchanged!

Answer 15

i coulnt do it @da_ScienceMan

Answer 16

Solve the system of equations using matrices. Use Gauss-Jordan elimination.

3x - 7 - 7z = 7
6x + 4y - 3z = 67
-6x - 3y + z = -62
A. {( 7, 1, 7)}
B. {( 14, 7, -7)}
C. {( -7, 7, 14)}
D. {( 7, 7, 1)}

Answer 17

ok why do u have the multiple choices? are those answers or what?

Answer 18

@Yacoub1993 brb!

Answer 19

ok so if we begin i can discuss and tell u which values u ll get so u write them down and we solve togewhther. It will make u become an expert in these type of equations. ready?

Answer 20

ok sorry lets knw when u are on @Yacoub93

Answer 21

Anyone help me Please

Answer 22

@da_ScienceMan

Answer 23

Do you have a TI-83 + calculator? There's a way to solve it on a calculator.

Answer 24

i have this one fx-991ES PLUS

Answer 25

is it similar @AngelicaLS

Answer 26

I've never heard of that one but do you see a button that says 2nd? If you hit that and the button underneath Matrix which is x^-1, it should take you to a menu.

Answer 27

matA or matB or matC

Answer 28

@AngelicaLS

Answer 29

doesn't matter. go with mat a. once you get to that menu, do you see dimensions? If so, change them to 3x4 for this problem.

Answer 30

ok

Answer 31

there is no 3x4

Answer 32

maximum is 3x3 @AngelicaLS

Answer 33

that's strange. let me try something on my calculator. one moment.

Answer 34

yeah, i don't know why your calculator doesn't allow dimensions larger than 3x3 so i can't teach you how to do it on yours. i do know that the answer is D (7,7,1). hopefully you can use that as a guide to find out the work behind it for yourself. :/