Question

i need help?

Answer 1

\(\huge ?\)

Answer 2

ok so i have a problem that i need you to check

Answer 3

Just are directly your question. What is the math problem ?

Answer 4

3s+3c=69 is a system of equations anyway the next problem is 5s+3c=91 and i need help solving it

Answer 5

s = 11, c = 12 very easy, what is the problem ? you just and s = (69-3c)/3 and replace it in your second equation to find c. Then you can find s.

Answer 6

oh ok

Answer 7

so where did you get 12 from

Answer 8

Ok. You have two equation 3s+3c=69 and 5s+3c=91. We subtract the terms of the two equations, so we have: (3s+3c) - (5s+3c) = 69 - 91, then 3s+3c - 5s-3c = 69 - 91 = -22, then 3s-5s = -22, then -2s = -22, then s = 22/2 = 11. Now you have s = 11, you can replace it in any of your two equations to find c, so you have 3s+3c=69, then 3*11+3c=69, then c = 12.

Answer 9

ohhhh

Answer 10

Is that ok for you ?

Answer 11

yes thank you

Answer 12

Welcome. I hope you understood how to solve a system of two equations with two variables.

Answer 13

wait did you subtract what

Answer 14

3s+3c=69
5s+3c=91
Thus by subtracting the terms of the two equations: (3s+3c) - (5s+3c) = 69 - 91. I guess this is very easy to understand, ins't it ?

Answer 15

yes but you subtract 69-91 right and you get 12

Answer 16

(3s+3c) - (5s+3c) = 69 - 91 = -22

Answer 17

oh so confused on the 12

Answer 18

you solve this, you will find s = 11 and c = 12.

Answer 19

I guess you need to read some lectures on "how to solve a system of two equations"

Answer 20

no i don't

Answer 21

??

Answer 22

just saying