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Chemistry 17 Online
OpenStudy (anonymous):

Buffer Solution Question

OpenStudy (anonymous):

A buffer solution is prepared by mixing 58.4 mL of 0.0846 M sodium dihydrogen citrate with 45.2 mL of 0.191 M sodium hydrogen citrate. a) Calculate the pH of this solution. - Found that pH to be 5.01 Now it asks: Calculate the pH of the buffer solution after the addition of 0.0343 g of sodium hydrogen citrate (Na2C3H5O(COOH)(COO)2) to the buffer solution above *Assume 5% approximation is valid and that the volume of solution does not change

OpenStudy (aaronq):

you're essentially adding it up the 2 amounts. So, convert 0.0343 g of sodium hydrogen citrate to moles, also convert 0.191 M sodium hydrogen citrate to moles (you know the volume). Add the moles together and find the new concentration. Plug it into the HH equation.

OpenStudy (anonymous):

so basically to get the sodium hydrogen citrate to be in moles I could just use the mass and divide it by its molar mass ? as to the sodium hydrogen citrate multiply it by the original volume to get 8.6332x10^-3 moles . then add those values together to get my mole value . Divide that by my original volume and input it back into my equation .

OpenStudy (anonymous):

@aaronq

OpenStudy (aaronq):

yeah. but use the total volume of the buffer when you find the new concentration

OpenStudy (anonymous):

Alright i got it thanks ^.^

OpenStudy (aaronq):

good stuff. no problem

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