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Physics 14 Online
OpenStudy (anonymous):

An electron has a speed of 1.65E7 m/s. If an uncertainty 44 nm in its potition is acceptable, what is the minimum possible percentage uncertianty in its linear momenttum?

OpenStudy (anonymous):

Heisenberg uncertainty principle: best you can do is dx dp = h, with dx the uncertainty in position and dp the uncertainty in momentum dp=d(mv) and h Planck's constant.

OpenStudy (anonymous):

thx :D

OpenStudy (anonymous):

You are quite welcome.

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