Question

An electron has a speed of 1.65E7 m/s. If an uncertainty 44 nm in its potition is acceptable, what is the minimum possible percentage uncertianty in its linear momenttum?

Answer 1

Heisenberg uncertainty principle: best you can do is
dx dp = h, with dx the uncertainty in position and dp the
uncertainty in momentum dp=d(mv) and h Planck's constant.

Answer 2

thx :D

Answer 3

You are quite welcome.