Completing square
Where's the equation?
\[75+\frac{ 100i }{ n }-\frac{ 100i^2 }{ n^2 }\]
just for simplicity, treat i/n = x so we have -100x^2 +100x +75 right ?
we need to have the co-efficient of x^2 as 1 so start by factoring -100 out \(-100 (x^2-........?)\)
actually i have to turn this form\[\frac{ 10 }{ n }\sqrt{75+\frac{ 100i }{ n }-\frac{ 100i }{ n^2 }} -->\frac{ 10 }{ n }\sqrt{100-(-5+\frac{ 10i }{ n })^2}\]
yes. we will get there onlt
only
ya how do i do that? can u help me step by step?
so start by factoring -100 out −100(x^2−........?)
you got the step where i took, i/n = x, right ?
-100(x^2-x-75/100)
yup!, after tht?
now divide the co-efficient of 'x' by 2
you mean the one outside the bracket?
ok, whats the co-efficient of x, first tell that in ax^2+bx+c, the co-efficient of x is b
ah okay haha, -1?
yes, so dividing it by 2 gives -1/2 now square it, what u get ?
1/4x^2?
actually there are standard steps to complete the square, we add and subtract, \((co-efficient ~of ~x /2)^2\)
where did x^2 come from ? square of -1/2 is just 1/4
a co-efficient is a constant multiplied with x
oh okay, i thought x also haha, okay thenit is -100(x^2-1/4x-0.75)
so we add and subtract 1/4 keep 0.75 as 3/4 -100 \((x^2 -x +1/4 -3/4 -1/4)\) got this ? i just added and subtracted 1/4 in what u previously had
oh so u mean the x and its coefficient are not in one term? i see, it make sense since coefficient would still be 1
then afterwards?
yes, we cannot change the expression, it was x^2 -x -3/4 before, it must be that afterwards too (notice that adding and subtracting 1/4 will not chnage the expression) and then do you notice a perfect square trinomial ? x^2 - x +1/4 = (..??.. )^2
like for example x^2 +2x+1 = (x+1)^2 \(x^2-x+1/4 = (x-what?)^2\)
uhm.. what is it haha, im kinda bothered with the 1/4 there
2 ways to find out, 1) see the last term, constant, 1/4 its like (a+b)^2 = a^2+2ab+b^2, the last term b^2 is the square of 'b' so here. we'll have square of ... ? 2) that "what?" term is same as the answer you got before squaring in the 2nd step
hm so (x-1/2)^2, sorry my head is abit laggy now haha
thats correct :) we have \(-100((x-1/2)^2 -1)\) right ? now just distribute the -100 inside
100(x-1/2)^2+100
-100 (x-1/2)^2 +100
oh ya haha then?
now 100 is 10^2 , so when it goes inside a square term, \(100 - [10(x-1/2)]^2\) got this ?
i missed a step, 100 - 10^2 (x-1/2)^2 100- [10 (x-1/2)]^2
okay got it then after?
whats 10 (x-1/2) = ... ? simplify
10x-5
and x = i/n
ahh! okay i see wow, nice! haha xD thank u very much! (:
you're welcome ^_^
did u draw that? emelove
draw what? @dan815
ur picture
oh, nah haha i put my face in an iphone app called moment cam haha, it shd be quite popular.. why do alot of people ask me, oh well.. haha
oh okay no wonder
cuz i was gonna say the eyes look crazy
like professional
looks can be deceiving.. :p u can try to dl it if u have iphone and see for urslf (:
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