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Help please?(: Is this equation a trigonometric identity? sin^2θ csc^2θ=sin^2θ+cos^2θ
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well you need a few trig identities on the right hand side you have \[\sin^2(\theta) + \cos^2(\theta) = 1\] so substitute 1 for sin^2 + cos^2 son csc^ 2 = 1 sin^2 so on the left you have \[\sin^2(\theta) \times \frac{1}{\sin^2(\theta)}\] so it should be easy to prove from here 1 = 1
Right, and since the left side is equal to the right side, it is indeed a trig identity? @campbell_st
yes.... by using the appropriate substitution, you're showing 1 = 1... so the trig identity is true
Thanks!
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