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Mathematics 21 Online
OpenStudy (anonymous):

y= cos 9x

OpenStudy (kc_kennylau):

and?

OpenStudy (anonymous):

Find the derivative of the following function

OpenStudy (kc_kennylau):

Do you know the chain rule? :)

OpenStudy (anonymous):

Yeah but I kinda forgot it

OpenStudy (kc_kennylau):

The chain rule is \(\dfrac{dy}{dx}=\dfrac{dy}{du}\cdot\dfrac{du}{dx}\) :)

OpenStudy (kc_kennylau):

Let \(u\) be \(9x\) :)

OpenStudy (anonymous):

Alright then tho i didnt get it that much xD

OpenStudy (anonymous):

There is 9 more btw

OpenStudy (kc_kennylau):

For example,\[\frac d{dx}\sin(5x)\]\[=\frac d{d(5x)}\sin(5x)\cdot\frac d{dx}5x\]\[=\cos(5x)\cdot5\]\[=5\cos(5x)\]

OpenStudy (kc_kennylau):

Get it? :)

OpenStudy (anonymous):

Hold on ?

OpenStudy (anonymous):

What about an answer to my question?

OpenStudy (kc_kennylau):

Can you try to do it by yourself first? :)

OpenStudy (anonymous):

Aight

OpenStudy (anonymous):

ddxcos(9x) =dd(9x)cos(9x)⋅ddx9x =sin(9x)⋅9 =9sin(9x)

OpenStudy (kc_kennylau):

well done, except the negative sign emerged from differentiating cosine :D

OpenStudy (anonymous):

What do you mean ?

OpenStudy (kc_kennylau):

-9sin(9x)

OpenStudy (anonymous):

Oh i see , but why ?

OpenStudy (kc_kennylau):

because \(\dfrac d{d\theta}\cos\theta=-\sin\theta\) :)

OpenStudy (anonymous):

Oh i see thank you

OpenStudy (anonymous):

What about the others ? I mean like the other questions.

OpenStudy (anonymous):

ShalI post it too

OpenStudy (kc_kennylau):

Just let \(u\) be whatever you feel appropriate :)

OpenStudy (kc_kennylau):

For example in \(y=(x+1)^4\), let \(u=x+1\) In \(y=\sin(\sqrt x)\), let \(u=\sqrt x\) :)

OpenStudy (anonymous):

How bout this , y=(cos 5x) (sin5x)

OpenStudy (kc_kennylau):

You can use the product rule for this :)

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