Mathematics
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OpenStudy (anonymous):
y= cos 9x
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OpenStudy (kc_kennylau):
and?
OpenStudy (anonymous):
Find the derivative of the following function
OpenStudy (kc_kennylau):
Do you know the chain rule? :)
OpenStudy (anonymous):
Yeah but I kinda forgot it
OpenStudy (kc_kennylau):
The chain rule is \(\dfrac{dy}{dx}=\dfrac{dy}{du}\cdot\dfrac{du}{dx}\) :)
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OpenStudy (kc_kennylau):
Let \(u\) be \(9x\) :)
OpenStudy (anonymous):
Alright then tho i didnt get it that much xD
OpenStudy (anonymous):
There is 9 more btw
OpenStudy (kc_kennylau):
For example,\[\frac d{dx}\sin(5x)\]\[=\frac d{d(5x)}\sin(5x)\cdot\frac d{dx}5x\]\[=\cos(5x)\cdot5\]\[=5\cos(5x)\]
OpenStudy (kc_kennylau):
Get it? :)
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OpenStudy (anonymous):
Hold on ?
OpenStudy (anonymous):
What about an answer to my question?
OpenStudy (kc_kennylau):
Can you try to do it by yourself first? :)
OpenStudy (anonymous):
Aight
OpenStudy (anonymous):
ddxcos(9x)
=dd(9x)cos(9x)⋅ddx9x
=sin(9x)⋅9
=9sin(9x)
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OpenStudy (kc_kennylau):
well done, except the negative sign emerged from differentiating cosine :D
OpenStudy (anonymous):
What do you mean ?
OpenStudy (kc_kennylau):
-9sin(9x)
OpenStudy (anonymous):
Oh i see , but why ?
OpenStudy (kc_kennylau):
because \(\dfrac d{d\theta}\cos\theta=-\sin\theta\) :)
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OpenStudy (anonymous):
Oh i see thank you
OpenStudy (anonymous):
What about the others ? I mean like the other questions.
OpenStudy (anonymous):
ShalI post it too
OpenStudy (kc_kennylau):
Just let \(u\) be whatever you feel appropriate :)
OpenStudy (kc_kennylau):
For example in \(y=(x+1)^4\), let \(u=x+1\)
In \(y=\sin(\sqrt x)\), let \(u=\sqrt x\) :)
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OpenStudy (anonymous):
How bout this , y=(cos 5x) (sin5x)
OpenStudy (kc_kennylau):
You can use the product rule for this :)