Integration substitution:
integral of \[\frac{ -x^4 }{ \sqrt{x^5+2} } dx\]
Can someone explain step by step how this substitution works please? Thank you.
assume x^5+2 =z^2 so that 5x^4 dx = 2z dz and then proceed further
Let u = x^5 + 2 du/dx = 5x^4 du = 5x^4 . dx 1/5 du = x^4 . dx
How does this substitute BACK into the original equation? This is what I don't understand.
sincethere is a sqrt in the denominator it would be better to assume the denominator as some perfect squares
Any input Zak?
Oh NO! I clicked close accidently :(
assume x^5+2 =z^2 so that 5x^4 dx = 2z dz so the required integration can be re written as integration of -(1/5) *(5x^4) dx/(sqrt(x^5+2) on substitution x^5+2 =z^2 and 5x^4 dx = 2z dz we have the question as (-1/5) 2zdz/sqrt(z^2) thus we e now the integration of (-2/5) dz which on integration gives (-2/5) z + c now we have z= sqrt(x^5+2) hence our answer is (-2sqrt(x^5+2)/5) + c
Thanks! :)
welcome dear well i hope u have understood
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