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solve the logarithmic equation: ln x +ln(x+1)=5
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hi @chelle1018 :) do you know the log property that \(\ln A+\ln B = \ln (AB)\) ?
using that property , left side will equal \(\ln [x(x+1)]\) got this ?
so: \[e^5=x(x+1)\] or \[e^5=x^2+x\]
actually you can rewrite it as:\[\frac{ e^5 }{ x }-x=1\]
so:\[\frac{ e^5 }{ x }-x=e^0\]
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x^2+x -e^5 =0 is quadratic equation, solve it using quadratic formula
multiply both sides by x:\[e^5-x^2=x\]
if you plug that quadratic equation into the quadratic formula you get \[x=\frac{ -1-\sqrt{1+4e^5} }{ 2 }\]
thats the answer
or \[x=\frac{ \sqrt{1+4e^5}-1 }{ 2 }\]
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