Question

Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2).

y = two thirdsx − 10

y = two thirdsx + 10

y = −three halvesx − 10

y = −three halvesx + 10

Answer 1

can you find the slope of 2x-3y =3 ?

Answer 2

yes i can
y=-3 and x = 2 ,c=-3
y=mx+c
-3=m2-3
-3+3=2m
0\2=m
m=0

Answer 3

hartnn
i did

Answer 4

thats incorrect...

Answer 5

how can i find it?

Answer 6

isolate y from
2x − 3y = 3

Answer 7

-y=3-2x
y=2x-3

Answer 8

-3y=3-2x
y=-1+2\3 x
here , b= -1 and m= +2\3
but we know that in perpendicular position we use m1m2=-1
m +2\3 =-1
m=-3\2
so m=-3\2
and the line passes from the (-8,2)
(x,y)=(-8,2)
y=mx+b
2=-8(-3\2)+b
2= 12+b
b=2-12
b=-10
now put it in the slope intercept from
y=-3\2x -10
this is the true answer
it means that C option is absolutly correct

Answer 9

Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2).

Perpendicular lines have negative reciprocal slopes.
First get your equation in slope-intercept form (y=mx+b).
by solving for y.
2x - 3y = 3
3y = 2x - 3
y = 2/3x - 1

the perpendicular slope is -3/2
Then plug in your (x,y) coordinates given and with your slope into.
y = mx +b
and Solve for the b value ( your y-intercept )
Do you understand so far?