Find and simplify the difference quotient [f(x+h)-f(x)]/h for the given function. f(x)=3x^2+2x+1
Do you have the answer just so I can see if I'm correct?
I do, however I think the answer is incorrect. That is why I am asking this question. The supposed answer is: \[6x+3h+2\]
how did you get that answer @anthonykanow
That's what I got, I'll explain the steps
that is not the supposed answer use the power rule
X^n = nX^n-1+...
the derivative of a constant is zero
@nincompoop I did not get that answer, my professor did. Also, this is not suppose to be solved using calculus.
[f(x+h)-f(x)]/h <-- definition of derivative (it is slightly incomplete, but it is known as the "difference quotient") plug your function into the definition and show it here
So when we are looking at a difference quotient problem we have to substitute the function into the formula we are given a couple of times, and we have to simplify. When we substitute, we get ((3(x+h)^2+2(x+h)+1)-(3x^2+2x+1))/h This simplifies to ((3(x^2+2xh+h^2)+2x+2h+1)-3x^2-2x-1)/h when we multiply out the three, we can see that many terms will cancel this leaves us with (6xh+3h^2+2h)/h and when we cancel the available h in each term we are left with 3h+6x+2
@nincompoop What answer did you arrive to? I do not think you are correct. This is a simple algebra problem.
@HiGhoCtaN399 Thank you very much. I have found my error.
what is the purpose of adding h in that equation?
I think it basically has to do with rates of change and limits and stuff but I'm not entirely sure what purpose the h serves.
difference quotient computes for the slope of a secant line the reason I brought up the power rule, because that is the basis of the limit (where h approaches zero but not equal to zero) you can't compute for the slope of the secant line if you are not given the points in a typical algebraic manipulation. it only gives you the general form.
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