Question

Find antiderivative
g(t) = 3 + t + t^2 / [sqrt(t) ]

Answer 1

question edited^

Answer 2

Well, firstly you can break it up into 3 parts, do you know how to find the antiderivative of the first 2 terms?

Answer 3

just to clarify, is it
(3+t+t^2) in the numerator
or ?
3+t is separate and only t^2 in the numerator?

Answer 4

first one

Answer 5

ooh...
that changes things

Answer 6

a little

Answer 7

thought so :)

Answer 8

you can rewrite it with each term seperately over sqrt(t) and then simplify to get,
3t^(-1/2) + t^(1/2) + t^(3/2)

Answer 9

its like separating out the numerator and then simplifying
(a+b+c)/d = a/d+b/d+c/d

Answer 10

Then you can just use the power rule for each individual term,
the antiderivative of x^n = [x^(n+1)]/(n+1)