x+1=y/4 and 4x=y/5
what's \(s\)? :)
He's probably asking us to find s...
But \(n\) equations \(n\) unknowns...
He just changed it to 5...
LOL wait how do you edit questions
Click edit? c:
x=1/4 y=5
lol ok @gioson5 There are 4 approaches: 1. Make \(x\) the subject of \((1)\) and substitute it into \((2)\). 2. Make \(y\) the subject of \((1)\) and substitute it into \((2)\). 3. Make \(x\) the subject of \((2)\) and substitute it into \((1)\). 4. Make \(y\) the subject of \((2)\) and substitute it into \((1)\).
How the heck does x=1/4? O_O WOAH. @kc_kennylau
lol @kittiwitti1 @Takuno don't just give out answers please :)
\[x=\frac{y}{4}-1,~y=5(4x)\]you decide which one to use in substitution
ok, because equation one equals y/4 and equation two equals y/5 so the ratio of (equation one)/(equation two) = 5/4. therefore look at the left hand side of both of the equations, (x+1)/(4x) = 5/4 and then you can use cross multiplication.
As I said there are 4 approaches lol @kittiwitti1
Well I don't want to consider all of 'em lol @kc_kennylau
gotta go bye D:
bye :/
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